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Pats All-Pro TE Gronkowski gets $54 million deal (Yahoo! Sports)

FILE - In this Jan 2, 2011, file photo, New England Patriots tight end Rob Gronkowski (87) celebrates his touchdown reception in front of wide receiver Brandon Tate (19) in the first quarter of an NFL football game against the Miami Dolphins in Foxborough, Mass. Gronkowski has agreed to a $  54 million deal with the Patriots, the richest contract for a tight end in NFL history. The six-year deal includes $  18.17 million guaranteed. (AP Photo/Michael Dwyer, File)

NEW YORK (AP) All-Pro Rob Gronkowski agreed Friday to a $ 54 million deal with the New England Patriots, the richest contract for a tight end in NFL history.



Yahoo! Sports – NFL News

Posted in NFL.




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